25n^2=65n

Solution for 25n^2=65n equation:

25n^2=65n

We move all terms to the left:

25n^2-(65n)=0

a = 25; b = -65; c = 0;
Δ = b2-4ac
Δ = -652-4·25·0
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-65}{2*25}=\frac{0}{50}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+65}{2*25}=\frac{130}{50}
=2+3/5
$